思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
if (arr[j] arr[j + 1]) { // 升序：前面的大于后面的就交换
，更多细节参见heLLoword翻译官方下载
Mort added that the gap between a potential developer expressing interest and actively contributing can be as little as a week. This also allows movement between roles—for example, an interior designer training in exterior designing or someone starting in quest design moving elsewhere if it’s not a good fit.
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